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AP EAMCET202017 Sep 2020Morning ShiftMathematicsCircleActual

The equation of a circle with centre ((5,4) ) and touch the (Y )-axis is

Options

  1. A(x^2+y^2-10 x-8 y-16=0 )
  2. B(x^2+y^2-10 x-8 y-61=0 )
  3. C(x^2+y^2+10 x+8 y+16=0 )
  4. D(x^2+y^2-10 x-8 y+16=0 )

Correct answer

D. (x^2+y^2-10 x-8 y+16=0 )

Step-by-step solution

Centre ((5,4) ) circle touches (Y )-axis So, radius (=5 ) units Equation of circle ( (x-5)^2+(y-4)^2=5^2 ) ( x^2+y^2-10 x-8 y+16=0 )

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