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MHT CET20243 May 2024Morning ShiftPhysicsWave OpticsActual

A single slit diffraction pattern is formed with light of wavelength 6195 Å . The second secondary maximum for this wavelength coincides with the third secondary maximum in the pattern for light of wavelength ' ₀ '. The value of ' ₀ ' is

Options

  1. A4180 Å
  2. B4425 Å
  3. C5330 Å
  4. D6235 Å

Correct answer

B. 4425 Å

Step-by-step solution

For n ^ th secondary maximum, array ll & x _ n = (2 n +1) D 2 a & For n =2, & x ₂= 5 D 2 a & and for n =3, x ₃= 7 ₀ D 2 a & Here, x ₂= x ₃ & 5 =7 ₀ & ₀= 5 7 = 5 6195 7 =4425 Å array

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