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MHT CET202312 May 2023Evening ShiftPhysicsWave OpticsActual

The ratio of intensities of two points on a screen in Young's double slit experiment when waves from the two slits have a path difference of 4 and 6 is ( 90^ =0, 60^ =0.5 )

Options

  1. A2: 1
  2. B2: 3
  3. C3: 4
  4. D3: 5

Correct answer

B. 2: 3

Step-by-step solution

The intensity at the point due to interference is given as I=I₁+I₂+2 I₁ I₂ For path difference 4 , the phase difference is ₁= 2 4 = 2 For path difference 6 , the phase difference is ₂= 2 6 = 3 Assuming equal intensity of the interfering waves i.e., I ₁= I ₂= I ₀ Equation (i) becomes, aligned & I=I₀+I₀+2 I₀ & I=2 I₀(1+ ) aligned For the given path difference, I₁=2 I₀ (1+ 2 ) . aligned & and I₂=2 I₀ (1+ 3 ) & I₁ I₂ = 1+ 2 1+ 3 aligned aligned I ₁ I ₂ & = 1+0 1+0.5 I ₁ I ₂ & = 1 1.5 = 2 3 aligned

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