AP EAMCET202017 Sep 2020Morning ShiftMathematicsCircleActual
Find the value of (m+n ), if the circumference of the circle (x^2+y^2+8 x+8 y-m=0 ) is bisected by the circle (x^2+y^2-2 x+4 y+n=0 ).
Options
- A-56
- B56
- C50
- D-34
Correct answer
A. -56
Step-by-step solution
Let (S₁ x^2+y^2+8 x+8 y-m=0 ) (S₂=x^2+y^2-2 x+4 y+n=0 ) Equation of common chord ( aligned & & S₁-S₂ & =0 & & 10 x+4 y-(m+n) & =0 & & 10 x+4 y & =(m+n) aligned ) Centre of bisected circle is ((-4,-4) ) which will lie on common chord So, ( (m+n)=-56 )