MHT CET202310 May 2023Morning ShiftPhysicsWave OpticsActual
Two sources of light 0.6 ~mm apart and screen is placed at a distance of 1.2 ~m from them. A light of wavelength 6000 Å used. Then the phase difference between the two light waves interfering on the screen at a point at a distance 3 ~mm from central bright band is
Options
- A6 radian
- B3 radian
- C4 radian
- D5 radian
Correct answer
D. 5 radian
Step-by-step solution
Fringe width, W= . D d = 6000 10⁻¹⁰ 1.2 0.6 10⁻³ =1.2 ~mm Number of fringes (n) = 3 1.2 =2.5 Phase difference, =2 n =2 2.5 =5