In a Fraunhofer diffraction at a single slit of width d and incident light of wavelength 5500 ~A , the firs minimum is observed at an angle 30^ . The first secondary maxima are observed at an angle =

Step-by-step solution

Slit width =d =5500 =5.5 10⁻⁷ ~m , ₁=30^ For first secondary minima, d ₁= = ₁ = 5.5 10⁻⁷ 30^ =11 10⁻⁷ For first secondary maxima, d ₁= 3 2 aligned & ₁= 3 2 d = 5.5 10⁻⁷ 2 11 10⁻⁷ = 3 4 & ₁= ⁻¹ ( 3 4 ) aligned