MHT CET20226 Aug 2022Morning ShiftPhysicsWave OpticsActual
Two waves having amplitudes in the ratio 5:1 produce interference. The ratio of the maximum to minimum intensity is
Options
- A6: 4
- B25: 1
- C3: 2
- D9: 4
Correct answer
D. 9: 4
Step-by-step solution
Let the amplitudes be 5 x and x respectively. The resultant waves will have maximum amplitude when both are in phase Therefore, amplitudes should add up to 5 x+x=6 x During destructive interference, the waves are out of phase Therefore, the resultant amplitude is x-5 x=-4 x Maximum intensity ( maximum amplitude )^2=36 x^2 Minimum intensity ( minimum amplitude )^2=16 x^2 The ratio of the maximum to minimum intensity = 36 16 = 9 4