MHT CET202124 Sep 2021Morning ShiftPhysicsWave OpticsActual
In Young's double slit experiment, the intensity at a point where path difference is 6 ( being the wavelength of light used) is I'. If ' I₀ ' denotes the maximum intensity, then I I₀ is equal to
Options
- A3 2
- B3 4
- C1 2
- D1 2
Correct answer
B. 3 4
Step-by-step solution
If I ' is the intensity of each wave, then the resultant intensity at a point is given by I =4 I ^ ^2 2 For maximum intensity, phase difference =0 I ₀=4 I ^ ^2 0=4 I ^ At a point where path difference is 6 , hence phase difference is aligned & 3 . & I =4 I ^ ^2 6 =3 I ^ & I I ₀ = 3 4 aligned