A Fraunhofer diffraction pattern due to a single slit of width 0 3 ~mm is obtained on a screen placed at a distance of 3 ~m from the slit. The first minima lie at 5 5 ~mm on either side of the central maximum on the screen. The wavelength o

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A Fraunhofer diffraction pattern due to a single slit of width 0 3 ~mm is obtained on a screen placed at a distance of 3 ~m from the slit. The first minima lie at 5 5 ~mm on either side of the central maximum on the screen. The wavelength of light used is

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Correct answer: B. 5500 Å

a=0.3 ~mm =0.3 10⁻³ ~m , D=3 ~m , x=5.5 ~mm =5.5 10⁻³ ~m x= D a = xa D =5.5 10⁻³ 0.3 10⁻³ 3 =5.5 10⁻⁷ ~m =5500 Å

A Fraunhofer diffraction pattern due to a single slit of width 0 3 ~mm is obtained on a screen placed at a distance of 3 ~m from the slit. The first minima lie at 5 5 ~mm on either side of the central maximum on the screen. The wavelength of light used is

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