MHT CET2019Evening ShiftPhysicsWave OpticsActual
Light of wavelength ' λ ' is incident on a single slit of width ‘a’ and the distance between slit and screen ‘D’. In diffraction pattern, if slit width is equal to the width of the central maximum then ‘D’ is equal to
Options
- Aa 2 λ
- Ba 2 2 λ
- Ca λ
- Da 2 λ
Correct answer
B. a 2 2 λ
Step-by-step solution
The width of central maximum is given by 2 y = 2 D λ a …. (i) where, λ = wavelength of incident light. Here, a =2y, then from Eq. (i) we get a = 2 D λ a ⇒ D = a 2 2 λ