MHT CET2011PhysicsWave Optics
In Young's double slit experiment if the slit widths are in the ratio 1: 9 . The ratio of the intensity at minima to that at maxima will be
Options
- A1
- B1 / 9
- C1,4
- D1 / 3
Correct answer
C. 1,4
Step-by-step solution
Amplitude of the superimposing waves are array l a₁ a₂ = ( 1 9 )^ 1 / 2 = 1 3 I_ minima I_ maxima = (a₁-a₂ )² (a₁+a₂ )² = 1 4 array