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MHT CET2009PhysicsWave Optics

In an interference experiment, third bright fringe is obtained at a point on the screen with a light of 700 ~nm . What should be the wavelength of the light source in order to obtain 5 th bright fringe at the same point?

Options

  1. A500 ~nm
  2. B630 ~nm
  3. C750 ~nm
  4. D420 ~nm

Correct answer

D. 420 ~nm

Step-by-step solution

n₁ ₁=n₂ ₂ 3 700=5 ₂ ₂=420 ~nm

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