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MHT CET202620 April 2026Evening ShiftPhysicsWaves and SoundActual

Two monoatomic ideal gases '1' and '2' of molecular masses m₁ and m₂ respectively are enclosed in separate containers kept at the same temperature. The ratio of the speed of sound in gas '1' to that in gas '2' is

Options

  1. Am₁ m₂
  2. Bm₂ m₁
  3. Cm₁ m₂
  4. Dm₂ m₁

Correct answer

B. m₂ m₁

Step-by-step solution

The speed of sound in an ideal gas is given by v = R T M , where M is the molar mass of the gas. Since M = m N_A , where m is the molecular mass and N_A is Avogadro's number, the speed of sound can be written as v = R T m N_A . Both gases are monoatomic, so they have the same adiabatic index . They are also at the same temperature T . Therefore, v 1 m . The ratio of the speed of sound in gas '1' to that in gas '2' is v₁ v₂ = m₂ m₁ . Answer: m₂ m₁

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