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MHT CET202617 April 2026Evening ShiftPhysicsWaves and SoundActual

Two sounding waves send waves at certain temperature in air of wavelength 50 cm and 50.5 cm repectively. The frequency of sources differ by 6 Hz. The velocity of sound in air at same temperature is

Options

  1. A330 m/s
  2. B313 m/s
  3. C303 m/s
  4. D300 m/s

Correct answer

C. 303 m/s

Step-by-step solution

Given ₁ = 50 cm = 0.5 m and ₂ = 50.5 cm = 0.505 m . The frequencies of the two waves are f₁ = v ₁ and f₂ = v ₂ , where v is the velocity of sound. Given the difference in frequencies is 6 Hz : f₁ - f₂ = 6 v 0.5 - v 0.505 = 6 v ( 1 0.5 - 1 0.505 ) = 6 v ( 2 - 200 101 ) = 6 v ( 202 - 200 101 ) = 6 v ( 2 101 ) = 6 v = 6 101 2 = 303 m/s Answer: 303 m/s

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