MHT CET202617 April 2026Morning ShiftPhysicsWaves and SoundActual
In case of stationary wave pattern, which of the following statement is CORRECT ?
Options
- AThe distance between consecutive antinodes is equal to the wavelength.
- BIn a pipe open at both ends when an air column is vibrated, only even harmonics are present.
- CWhen an air column is vibrated in a pipe closed at one end, all harmonics are present.
- DIn the case of a stretched string, when vibrated frequency of the first overtone is same as the second harmoni
Correct answer
D. In the case of a stretched string, when vibrated frequency of the first overtone is same as the second harmoni
Step-by-step solution
The distance between consecutive antinodes in a stationary wave is 2 , not . In a pipe open at both ends, all harmonics (both even and odd) are present, with frequencies f_n = n v 2L where n = 1, 2, 3, In a pipe closed at one end, only odd harmonics are present, with frequencies f_n = (2n-1) v 4L where n = 1, 2, 3, In a stretched string fixed at both ends, the frequencies of vibration are f_n = n v 2L . The fundamental frequency is f₁ (first harmonic). The first overtone corresponds to the next higher frequency, wh