Two waves Y₁ = 0.25 316t and Y₂ = 0.25 310t are propagating along the same direction. The number of beats produced per second are

Step-by-step solution

Given equations of waves are Y₁ = 0.25 316t and Y₂ = 0.25 310t . Comparing with the standard wave equation Y = A t , the angular frequencies are: ₁ = 316 rad/s ₂ = 310 rad/s The corresponding frequencies are: f₁ = ₁ 2 = 316 2 = 158 Hz f₂ = ₂ 2 = 310 2 = 155 Hz The number of beats produced per second is given by the difference in frequencies: f_ beat = f₁ - f₂ = 158 - 155 = 3 Answer: 3