When the observer moves towards a stationary source with velocity ' V₁ ', the apparent frequency of the emitted note is ' F₁ '. When the observer moves away from the source with velocity ' V₁ ', the apparent frequency is ' F₂ '. If 'V' is the speed of sound in air and F₁/F₂ = 2 , then V/V₁ =

Step-by-step solution

Using the Doppler effect formula, the apparent frequency when the observer moves towards the stationary source is given by F₁ = F₀ ( V + V₁ V ) When the observer moves away from the stationary source, the apparent frequency is F₂ = F₀ ( V - V₁ V ) Given that F₁ F₂ = 2 , we can write V + V₁ V - V₁ = 2 V + V₁ = 2V - 2V₁ 3V₁ = V V V₁ = 3 Answer: 3