Two waves are represented by the equations, y₁ = a ( t + kx + 0.57) m and y₂ = a ( t + kx) m, where x is in metre and t is in second. What is the phase difference between them? ( = 3.14 )

Step-by-step solution

The given wave equations are: y₁ = a ( t + kx + 0.57) y₂ = a ( t + kx) Expressing the second wave in terms of sine: y₂ = a ( t + kx + 2 ) The phase difference between the two waves is: = ( t + kx + 2 ) - ( t + kx + 0.57) = 2 - 0.57 Substituting = 3.14 : = 3.14 2 - 0.57 = 1.57 - 0.57 = 1.0 radian Answer: 1.0 radian