MHT CET202613 April 2026Morning ShiftPhysicsWaves and SoundActual
A sonometer wire is vibrating in third overtone. There are
Options
- A5 nodes and 4 antinodes
- B4 nodes and 5 antinodes
- C4 nodes and 4 antinodes
- D5 nodes and 5 antinodes
Correct answer
A. 5 nodes and 4 antinodes
Step-by-step solution
A sonometer wire is fixed at both ends. For a string fixed at both ends, the p -th overtone corresponds to the (p+1) -th harmonic. The third overtone corresponds to the 4 -th harmonic. In the 4 -th harmonic, the wire vibrates in 4 loops. Each loop contains one antinode, so the number of antinodes is 4 . The number of nodes is one more than the number of loops, which is 4 + 1 = 5 . Thus, there are 5 nodes and 4 antinodes. Answer: 5 nodes and 4 antinodes