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MHT CET202527 Apr 2025Evening ShiftPhysicsWaves and SoundActual

When two sound waves having amplitude ' 3 ' and ' 5 ' units are superimposed then the ratio of maximum to minimum intensity of wave produced is

Options

  1. A2:1
  2. B5:3
  3. C4:1
  4. D16:1

Correct answer

A. 2:1

Step-by-step solution

Let the amplitudes of the two sound waves be A₁ = 3 units and A₂ = 5 units. The maximum resultant amplitude occurs during constructive interference: A_ max = A₁ + A₂ = 8 units. The minimum resultant amplitude occurs during destructive interference: A_ min = |A₁ - A₂| = 2 units. Since intensity is proportional to the square of amplitude, the ratio is: I_ max I_ min = ( A_ max A_ min )^2 = ( 8 2 )^2 = 16 The ratio of maximum to minimum intensity is 16:1. The correct option is D.

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