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MHT CET202525 Apr 2025Morning ShiftPhysicsWaves and SoundActual

At poles, a stretched wire of a given length vibrates in unison with a tuning fork. At the equator, for same setting, to produce resonance with same fork, the vibrating length of wire

Options

  1. Ashould be decreased.
  2. Bshould be increased.
  3. Cshould be same.
  4. Dshould be three times.

Correct answer

A. should be decreased.

Step-by-step solution

The frequency of a vibrating stretched wire is given by f = 1 2L T , where L is the wire length, T is the tension, and is the linear mass density. For resonance with the same tuning fork, f remains constant, and is unchanged. The tension T equals the weight of the hanging mass, so T = mg . At the poles, g is unchanged, but at the equator, the effective gravity is reduced to g - R ^2 , where R is Earth's radius and is its angular velocity. Consequently, T_ equator = m(g - R ^2) Since f 1 L T and f is constant, L T .

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