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AP EAMCET201920 Apr 2019Evening ShiftMathematicsCircleActual

If the circle x^2+y^2+6 x-2 y+k=0 bisects the circumference of the circle x^2+y^2+2 x-6 y-15=0 , then k=

Options

  1. A21
  2. B-21
  3. C-23
  4. D23

Correct answer

C. -23

Step-by-step solution

Equation of given circles array r S₁: x^2+y^2+6 x-2 y+k=0 and S₂: x^2+y^2+2 x-6 y-15=0 array Since, the circle S₁ bisects the circumference of the circle S₂ , then the common of circles S₁ and S₂ will passing through the centre of circle S₂(-1,3) . Equation of common chord of circles S₁ and S₂ is Chord (i) is passes through point (-1,3) , so -4+12+k+15=0 k=-23 Hence, option (c) is correct.

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