A sonometer wire is stretched by hanging a metal bob, the fundamental frequency of the wire is ' n₁ '. When the bob is completely immersed in water, the frequency of vibration of wire becomes ' n ₂ '. The relative density of the metal of the bob is

Step-by-step solution

n = 1 2 ~L ~T The sonometer wire is stretched by a metal bob. Hence, we can write, T=m g=W where W is the weight of the metal bob. array ll & From(i), & n ₁= 1 2 L W₁ , n₂= 1 2 L W₂ & W₁ W₂ = n₁^2 n₂^2 array Relative density ( )= weight in air loss of weight in water W ₁ ~W ₁- W ₂ = n ₁^2 n ₁^2- n ₂^2