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MHT CET20243 May 2024Evening ShiftPhysicsWaves and SoundActual

The end correction of resonance tube is 1 cm . If the shortest length resonating with a tuning fork is 15 cm , the next resonating length will be

Options

  1. A35 cm
  2. B40 cm
  3. C47 cm
  4. D64 cm

Correct answer

C. 47 cm

Step-by-step solution

Let the shortest length be denoted as l₁=15.0 ~cm The end correction, e =1.0 ~cm l₁+ e = 4 Now, l₂+ e = 3 4 array ll & l₁+ e l₂+ e = 1 3 & 15+1 l₂+1 = 1 3 & l₂+1=48 & l₂=47 ~cm array

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