A sonometer wire is stretched by hanging a metal bob. The fundamental frequency of vibration of wire is ' n₁ '. When the bob is completely immersed in water, the frequency of vibration of wire becomes ' n₂ '. The relative density of the met

Question

A sonometer wire is stretched by hanging a metal bob. The fundamental frequency of vibration of wire is ' n₁ '. When the bob is completely immersed in water, the frequency of vibration of wire becomes ' n₂ '. The relative density of the metal of the bob is

Quantrex Academy · Accepted Answer

Correct answer: C. n₁^2 n₁^2-n₂^2

n = 1 2 ~L ~T The sonometer wire is stretched by a metal bob, T = mg = W where W is weight of metal bob array ll & From(i), & n ₁= 1 2 ~L ~W ₁ , n ₂= 1 2 ~L ~W ₂ & ~W ₁ ~W ₂ = n ₁^2 n ₂^2 & Relative density ( )= weight in air loss of weight in water & W ₁ ~W ₁- W ₂ = n ₁^2 n ₁^2- n ₂^2 array

A sonometer wire is stretched by hanging a metal bob. The fundamental frequency of vibration of wire is ' n₁ '. When the bob is completely immersed in water, the frequency of vibration of wire becomes ' n₂ '. The relative density of the metal of the bob is

Options

Correct answer

Step-by-step solution

More from Waves and Sound