Two sounding sources send waves at certain temperature in air of wavelength 50 ~cm and 50.5 ~cm respectively. The frequency of sources differ by 6 ~Hz . The velocity of sound in air at same temperature is

Step-by-step solution

v = n Since, both the sound sources are at same temperature, velocity of sound in both cases would be the same. aligned & v = (50 n _ l ) cm / s .....(i) & v = (50.5 n ₂ ) cm / s ....(ii) & n ₁ n ₂ = 50.5 50 ....[From (i) and (ii)] & n ₁- n ₂ n ₂ = 50.5-50 50 & aligned array ll & 6 n ₂ = 0.50 50 = 1 100 . ( n ₁- n ₂=6 ~Hz ) & n ₂=600 ~Hz & v = 50.5 600 100 ~m / s [ From (ii) ] & v =303 ~m / s array