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MHT CET202312 May 2023Morning ShiftPhysicsWaves and SoundActual

41 tuning forks are arranged in increasing order of frequency such that each produces 5 beats/second with next tuning fork. If frequency of last tuning fork is double that of frequency of first fork. Then frequency of first and last fork is

Options

  1. A400,200 ~Hz
  2. B200,400 ~Hz
  3. C100,200 ~Hz
  4. D205,410 ~Hz

Correct answer

B. 200,400 ~Hz

Step-by-step solution

Let Frequency of 1^ st tuning fork be = n ₁ frequency of 41^ st tuning fork =n₄₁ Now, array ll & n ₄₁= n ₁+(41-1) 5 & But, n ₄₁=2 n ₁ & 2 n ₁= n ₁+200 & n ₁=200 ~Hz & n ₄₁=400 ~Hz array

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