A sound of frequency 480 ~Hz is emitted from the stringed instrument. The velocity of sound in air is 320 ~m / s . After completing 180 vibrations, the distance covered by a wave is

Step-by-step solution

Given: v =320 ~m / s , f =480 ~Hz , ~N =180 v = f = v f Substituting the values, we get = 320 480 = 2 3 The total distance covered after 180 vibrations is aligned & D = N & D =180 2 3 & D =120 ~m aligned