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MHT CET20239 May 2023Evening ShiftPhysicsWaves and SoundActual

If the end correction of an open pipe is 0.8 ~cm , then the inner radius of that pipe is

Options

  1. A1 3 ~cm
  2. B2 3 ~cm
  3. C3 2 ~cm
  4. D0.2 ~cm

Correct answer

B. 2 3 ~cm

Step-by-step solution

For an open pipe, e =0.6 ~d aligned & d = e 0.6 & 2 r = e 0.6 & r = 0.8 1.2 = 2 3 ~cm aligned

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