In resonance tube experiment, the first and second resonance are heard when water level is 24.1 ~cm and 74.1 ~cm respectively, below the open end of the tube. The inner diameter of the tube is

Step-by-step solution

Let the end correction be x , then the diameter D of the one end open tube will be given by, D= x 0.3 For first resonance: x+h= 4 x+24.1= 4 ---(1) And, for second resonance: x+H= 3 4 x+74.1= 3 4 ---(2) On taking the ratio of equation (1) and (2) and solving aligned & x=0.9 ~cm & 0.3 D=0.9 ~cm & D=3 ~cm aligned