A uniform wire of length L , diameter D and density is stretched by a tension T length L and the diameter D is

Step-by-step solution

Given, Frequency =f , Diameter =D , Length =L , Density = and Tension =T Now, we know that f= c , f= 1 2 L T where is mass per unit length And mass per unit length is related to density via, = ( D^2 4 ) 1 So, the frequency is f= 1 2 L T ( D^2 4 ) f 1 L D