For a particular sound wave propagating in air, a path difference between two points is 0.54 ~m which is equivalent to phase difference of (1.87 ) . If the velocity of sound wave in air is 330 ~m / s , the frequency of this wave is

Step-by-step solution

The correct option is (B). Concept: Path difference and phase difference are related by, 2 X = where x is the path difference, the phase difference and the wavelength. The velocity of a wave is given by: v= f , where f is the frequency. Combining the above two equations: f= v 2 x Given, x=0.54 ~m , =(1.8 ) and v =330 ~m / s , therefore, f = (1.8 )(330 ~m / s ) 2 (0.54 ~m ) =550 ~Hz