The fundamental frequency of a closed pipe is 400 ~Hz . If 1 / 3^ rd pipe is filled with water, the frequency of 2^ nd harmonic of the pipe will be (Neglect end correction)

Step-by-step solution

Fundamental frequency of closed pipe, array l n= V 4 L =400 V=400 4 L array If 1 3 rd of pipe is filled with water, then remaining length of air column is L- L 3 = 2 L 3 . Now, fundamental frequency = v 4 ( 2 L 3 ) = 3 v 8 L The second harmonic of the pipe =3 fundamental frequency array l =3 ( 3 v 8 ~L ) =3 3 400 4 ~L 8 ~L =1800 ~Hz array