When an open pipe is closed from one end then the third overtone of the closed pipe is higher in frequency by 150 Hz than the second overtone of an open pipe. The fundamental frequency of the open-end pipe will be

Step-by-step solution

Let f 0 = v 0 2 L be the fundamental frequency of the open pipe ∴ is second overtone is 3 f 0 = 3 v 0 2 L Let f = v 0 4 L be the fundamental frequency of close pipe. And third overtone of the organ pipe closed at one end only is, f 3 c l o s e d = 7 4 v 0 L As given 7 v 0 4 L - 3 v 0 2 L = 150 7 4 - 6 4 v 0 L = 150 ∴ v 0 4 L = 150 v 0 2 L = 300 Hz