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MHT CET2011PhysicsWaves and Sound

For the stationary wave y=4 ( x 15 ) (96 t) the distance between a node and the next antinode is

Options

  1. A7.5
  2. B15
  3. C22.5
  4. D30

Correct answer

A. 7.5

Step-by-step solution

On comparing given equation with standard equation, we get array l 2 = 15 =30 array Distance between the node and antinode = 4 = 30 4 =7.5

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