The work done by a force on body of mass 5 ~kg to accelerate it in the direction of force from rest to 20 ~m / s in 10 second is

Step-by-step solution

The correct option is (B). Concept: According to the work-energy theorem: Total work done by all forces (conservative or non - conservative) = Change in K.E. W = 1 2 mv ^2= 1 2 5 20^2=10^3 ~J