AP EAMCET201726 Apr 2017Evening ShiftMathematicsCircleActual
If (3,-1) is one end of a diameter of the circle x^2+y^2-2 x+4 y=0 , then the equation of the tangent at the other end of that diameter is
Options
- A2 x+y-5=0
- B2 x+y+5=0
- Cx+2 y+5=0
- Dx+2 y-5=0
Correct answer
B. 2 x+y+5=0
Step-by-step solution
No solution. Refer to answer key.