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AP EAMCET201725 Apr 2017Evening ShiftMathematicsCircleActual

Let , be the roots of x^2+5 x+6=0 and , be the roots of y^2+6 y+7=0 . Then the equation of the circle with ( , ) and ( , ) as the extremities of a diameter is

Options

  1. Ax^2+y^2+5 x+6 y+10=0
  2. Bx^2+y^2+5 x+6 y+11=0
  3. Cx^2+y^2+5 x+6 y+13=0
  4. Dx^2+y^2+5 x+6 y+12=0

Correct answer

C. x^2+y^2+5 x+6 y+13=0

Step-by-step solution

No solution. Refer to answer key.

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