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AP EAMCET201725 Apr 2017Morning ShiftMathematicsCircleActual

The locus of the point of intersection of the tangents to the circle x^2+y^2=a^2 which make complimentary angles with the X -axis is

Options

  1. Ax^2-y^2=0
  2. Bx^2+y^2=0
  3. Cx y=0
  4. Dx^2+y^2=2 a^2

Correct answer

A. x^2-y^2=0

Step-by-step solution

No solution. Refer to answer key.

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