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AP EAMCET2015MathematicsCircle

The equation of the circle passing through (2,0) and (0,4) and having the minimum radius, is

Options

  1. Ax^2 + y^2 = 20
  2. Bx^2 + y^2 - 2x - 4y = 0
  3. Cx^2 + y^2 = 4
  4. Dx^2 + y^2 = 16

Correct answer

B. x^2 + y^2 - 2x - 4y = 0

Step-by-step solution

No solution. Refer to answer key.

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