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MHT CET 202625 AprilEvening Shift
Exam
MHT CET
Year
2026
Date
25 April
Shift
Evening Shift
Subject
Biology
Chapter
Sexual Reproduction in Flowering Plants

MHT CET 2026 · 25 April · Evening Shift · Biology · Sexual Reproduction in Flowering Plants

Given below are two statements. Statement I - Adventive embryony...

Given below are two statements.
Statement I - Adventive embryony gives rise to a condition called polyembryony.
Statement II - Generally, Nicotiana plants produced by non-recurrent apomixis are sterile and do not produce sexually.
In the light of the above statements, select the correct option given below:

Options

  1. ABoth statement I and statement II are correct
  2. BBoth statement I and statement II are incorrect
  3. CStatement I is correct but statement II is incorrect
  4. DStatement I is incorrect but statement II is correct

Correct answer

A. Both statement I and statement II are correct

Step-by-step solution

Statement I is correct because adventive embryony involves the formation of embryos directly from diploid sporophytic cells (such as the nucellus or integuments) of the ovule. These embryos develop alongside the zygotic embryo, leading to the presence of multiple embryos in a single seed, a condition known as polyembryony. Examples include Citrus and Mango.

Statement II is correct because in non-recurrent apomixis, the embryo develops from a haploid cell (such as an unfertilized egg cell) without fertilization. The resulting plants are haploid. Since haploid plants lack homologous chromosomes, they cannot undergo normal meiosis, making them sterile and unable to reproduce sexually. This is observed in plants like Nicotiana.

Therefore, both statements are correct.

Answer: Both statement I and statement II are correct
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