Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
AP EAMCET2009MathematicsCircle

The locus of centre of a circle which passes through the origin and cuts off a length of 4 unit from the line x=3 is

Options

  1. Ay^2+6 x=0
  2. By^2+6 x=13
  3. Cy^2+6 x=10
  4. Dx^2+6 y=13

Correct answer

B. y^2+6 x=13

Step-by-step solution

Let centre of circle be C(-g,-f) , then equation of circle passing through origin be x^2+y^2+2 g x+2 f y=0 array lc Distance, d=|-g-3|=g+3 In A B C, & (B C)^2=A C^2+B A^2 & g^2+f^2=(g+3)^2+2^2 & g^2+f^2=g^2+6 g+9+4 & f^2=6 g+13 array Hence, required locus is y^2+6 x=13

Practice Circle on Quantrex Academy →

More from Circle

A circle touches both the coordinate axes and the straight line L 4 x +3 y -6=0 in the first quadrant. If this circle lies below the line L =0 , then the equation of that circle is 2025If the smallest circle through the points of intersection of x^2+y^2=a^2 and x +y =p, 0 < p < a is x^2+y^2-a^2+ (x +y -p)=0 then = 2025If the lines 3 x-4 y+4=0 and 6 x-8 y-7=0 are the tangents to the same circle, then the area of that circle (in sq.units) is 2025Circles are drawn through the point (2,0) to cut intercepts of length 5 units on the X -axis. If their centre lie in the first quadrant, then their equation is 2025The circles x^2+y^2-2 x-4 y-4=0 and x^2+y^2+2 x+4 y-11=0 2025If the line 4 x-3 y+7=0 touches the circle x^2+y^2-6 x+4 y-12=0 at ( , ) , then +2 = 2025The slope of the common tangent drawn to the circles x^2+y^2-4 x+12 y-216=0 and x^2+y^2+6 x-12 y+36=0 is 2025If r₁ and r₂ are radii of two circles touching all the four circles (x r)^2+(y r)^2=r^2 , then r₁+r₂ r = 2025 Full Circle list All AP EAMCET PYQs