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AP EAMCET2008MathematicsCircle

The radius of the circle with the polar equation r^2-8 r( 3 + )+15=0 is

Options

  1. A8
  2. B7
  3. C6
  4. D5

Correct answer

B. 7

Step-by-step solution

Given polar equation of circle is r^2-8 r( 3 + )+15=0 or r^2-8( 3 r +r )+15=0 where r =x and y=r . It can be rewritten in cartesian form aligned & x^2+y^2-8( 3 x+y)+15=0 & x^2+y^2-8 3 x-8 y+15=0 & Now, radius = (4 3 )^2+(4)^2-15 & = 48+16-15 =7 & aligned

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