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AP EAMCET2007MathematicsCircle

The equation of the circle of radius 3 that lies in the fourth quadrant and touching the lines x=0 and y=0 is

Options

  1. Ax^2+y^2-6 x+6 y+9=0
  2. Bx^2+y^2-6 x-6 y+9=0
  3. Cx^2+y^2+6 x-6 y+9=0
  4. Dx^2+y^2+6 x+6 y+9=0

Correct answer

A. x^2+y^2-6 x+6 y+9=0

Step-by-step solution

Given, radius =3 , Since, the circle touching both the coordinate axes in 4th quadrant, so equation is gathered (x-3)^2+(y+3)^2=3^2 x^2+9-6 x+y^2+9+6 y=9 x^2+y^2-6 x+6 y+9=0 gathered

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