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AP EAMCET2007MathematicsCircle

The inverse point of (1,2) with respect to the circle x^2+y^2-4 x-6 y+9=0 is

Options

  1. A(0,0)
  2. B(1,0)
  3. C(0,1)
  4. D(1,1)

Correct answer

C. (0,1)

Step-by-step solution

Inverse point of P(1,2) w.r.t. the circle is the foot of the perpendicular of P on the polar of P . Given circle is x^2+y^2-4 x-6 y+9=0 Polar of P(1,2) is array rrrr & & x 1+y 2-2(x+1)-3(y+2)+9=0 & x+2 y-2 x-2-3 y-6+9=0 & x+y-1=0 array Verifying inverse point of P is (0,1) .

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