AP EAMCET2006MathematicsCircle
The number of common tangents to the two circles x^2+y^2-8 x+2 y=0 and x^2+y^2-2 x-16 y+25=0 is :
Options
- A1
- B2
- C3
- D4
Correct answer
B. 2
Step-by-step solution
The equations of circles are x^2+y^2-8 x+2 y=0 and x^2+y^2-2 x-16 y+25=0 The centre and radius of first circle are C₁(4,-1) and 17 respectively. Also the centre and radius of second circle are C₂(1,8) and 40 respectively. C₁ C₂= (1-4)^2+(8+1)^2 = 9+81 = 90 and r₁+r₂= 17 + 40 C₁ C₂ < r₁+r₂ These two circles internally Thus the number of common tangents is 2 .