MHT CET 202625 AprilEvening Shift
- Exam
- MHT CET
- Year
- 2026
- Date
- 25 April
- Shift
- Evening Shift
- Subject
- Chemistry
- Chapter
- Polymers
MHT CET 2026 · 25 April · Evening Shift · Chemistry · Polymers
Identify a monomer used to prepare nylon 6,6 along with...
Identify a monomer used to prepare nylon 6,6 along with hexamethylene-diamine.
Options
- Aadipic acid
- Bpicric acid
- Cphthalic acid
- Dterephthalic acid
Correct answer
A. adipic acid
Step-by-step solution
Nylon 6,6 is a condensation polymer formed by the reaction of hexamethylenediamine and adipic acid under high pressure and at high temperature.
The reaction involves the elimination of water molecules to form amide linkages.
The monomers of Nylon 6,6 are hexamethylenediamine (H_2N-(CH_2)_6-NH_2).
Answer: adipic acid
The reaction involves the elimination of water molecules to form amide linkages.
The monomers of Nylon 6,6 are hexamethylenediamine (H_2N-(CH_2)_6-NH_2).
Answer: adipic acid