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MHT CET 202622 AprilMorning Shift
Exam
MHT CET
Year
2026
Date
22 April
Shift
Morning Shift
Subject
Chemistry
Chapter
Redox Reactions

MHT CET 2026 · 22 April · Morning Shift · Chemistry · Redox Reactions

Predict the oxidation number of of 'C' in K_2C_2O_4 and in CH_2Cl_2...

Predict the oxidation number of of 'C' in K2C2O4\text{K}_2\text{C}_2\text{O}_4 and in CH2Cl2\text{CH}_2\text{Cl}_2.

Options

  1. A+3+3 and +2+2
  2. B+3+3 and 00
  3. C−3-3 and +2+2
  4. D+3+3 and −2-2

Correct answer

B. +3+3 and 00

Step-by-step solution

Let the oxidation number of C\text{C} in K2C2O4\text{K}_2\text{C}_2\text{O}_4 be xx.

The oxidation number of K\text{K} is +1+1 and O\text{O} is −2-2.

2(+1)+2x+4(−2)=02(+1) + 2x + 4(-2) = 0

2+2x−8=02 + 2x - 8 = 0

2x=6⇒x=+32x = 6 \Rightarrow x = +3

Let the oxidation number of C\text{C} in CH2Cl2\text{CH}_2\text{Cl}_2 be yy.

The oxidation number of H\text{H} is +1+1 and Cl\text{Cl} is −1-1.

y+2(+1)+2(−1)=0y + 2(+1) + 2(-1) = 0

y+2−2=0⇒y=0y + 2 - 2 = 0 \Rightarrow y = 0

The oxidation numbers of C\text{C} are +3+3 and 00.

Answer: +3+3 and 00
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