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AP EAMCET2004MathematicsCircle

If the line 3 x-2 y+6=0 meets X -axis and Y -axis, respectively at A and B , then the equation of the circle with radius A B and centre at A is

Options

  1. Ax^2+y^2+4 x+9=0
  2. Bx^2+y^2+4 x-9=0
  3. Cx^2+y^2+4 x+4=0
  4. Dx^2+y^2+4 x-4=0

Correct answer

B. x^2+y^2+4 x-9=0

Step-by-step solution

Since, the line 3 x-2 y+6=0 meets the coordinates axes, therefore Points are A(-2,0) and B(0,3) . Radius =A B= 2^2+3^2 = 13 The equation of circle, whose centre (-2,0) and radius 13 , is aligned & (x+2)^2+(y-0)^2=( 13 )^2 & x^2+y^2+4 x+4=13 & x^2+y^2+4 x-9=0 & aligned

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