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MHT CET Medical202625 April 2026Evening ShiftChemistryStructure of AtomActual

Calculate the de-Broglie wavelength of an electron having velocity 1000 ms ⁻¹ [ h = 6.626 10⁻³⁴ js , mass of an electron = 9.1 10⁻³¹ kg ]

Options

  1. A7.28 10⁻⁷ m
  2. B6.68 10⁻⁷ m
  3. C7.76 10⁻⁷ m
  4. D7.45 10⁻⁷ m

Correct answer

A. 7.28 10⁻⁷ m

Step-by-step solution

The de-Broglie wavelength is given by the formula: = h mv Substituting the given values: = 6.626 10⁻³⁴ 9.1 10⁻³¹ 1000 = 6.626 10⁻³⁴ 9.1 10⁻²⁸ = 0.728 10⁻⁶ m = 7.28 10⁻⁷ m Answer: 7.28 10⁻⁷ m

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